println with no arguments accidentally doesn't print a newline.
Introduced at CL 55097
Fixes #21808
Change-Id: I9fc7b4271b9b31e4c9b6078f055195dc3907b62c
Reviewed-on: https://go-review.googlesource.com/62390
Run-TryBot: Keith Randall <khr@golang.org>
Reviewed-by: Emmanuel Odeke <emm.odeke@gmail.com>
TryBot-Result: Gobot Gobot <gobot@golang.org>
s := nn.List.Slice()
t := make([]*Node, 0, len(s)*2)
for i, n := range s {
- x := " "
- if len(s)-1 == i {
- x = "\n"
+ t = append(t, n)
+ if i != len(s)-1 {
+ t = append(t, nodstr(" "))
}
- t = append(t, n, nodstr(x))
}
+ t = append(t, nodstr("\n"))
nn.List.Set(t)
}
--- /dev/null
+// run
+
+// Copyright 2017 The Go Authors. All rights reserved.
+// Use of this source code is governed by a BSD-style
+// license that can be found in the LICENSE file.
+
+// Make sure println() prints a blank line.
+
+package main
+
+import "fmt"
+
+func main() {
+ fmt.Println("A")
+ println()
+ fmt.Println("B")
+}