Uintptr.Or returns the old value, just like all of the other Or
functions. This was a typo in the original CL 544455.
For #75607.
Fixes #75610.
Change-Id: I260959e7e32e51f1152b5271df6cc51adfa02a4d
Reviewed-on: https://go-review.googlesource.com/c/go/+/706816
Reviewed-by: Michael Knyszek <mknyszek@google.com>
Reviewed-by: Mauri de Souza Meneguzzo <mauri870@gmail.com>
LUCI-TryBot-Result: Go LUCI <golang-scoped@luci-project-accounts.iam.gserviceaccount.com>
Auto-Submit: Michael Pratt <mpratt@google.com>
(cherry picked from commit
d70ad4e740e24b4b76961c4b56d698fa23668aa2)
Reviewed-on: https://go-review.googlesource.com/c/go/+/706856
func (x *Uintptr) And(mask uintptr) (old uintptr) { return AndUintptr(&x.v, mask) }
// Or atomically performs a bitwise OR operation on x using the bitmask
-// provided as mask and returns the updated value after the OR operation.
+// provided as mask and returns the old value.
func (x *Uintptr) Or(mask uintptr) (old uintptr) { return OrUintptr(&x.v, mask) }
// noCopy may be added to structs which must not be copied