From: Russ Cox Date: Fri, 7 Dec 2012 16:58:44 +0000 (-0500) Subject: undo CL 6845121 / 79603a5e4cda X-Git-Tag: go1.1rc2~1695 X-Git-Url: http://www.git.cypherpunks.su/?a=commitdiff_plain;h=ff2534e076a01445f5852f0fab7a3017ee65c8ba;p=gostls13.git undo CL 6845121 / 79603a5e4cda This changes the output of rand.Seed(0) perm := rand.Perm(100) When giving the same seeds to Go 1.0 and Go 1.1 programs I would like them to generate the same random numbers. ««« original CL description math/rand: remove noop iteration in Perm The first iteration always do `m[0], m[0] = m[0], m[0]`, because `rand.Intn(1)` is 0. fun note: IIRC in TAOCP version of this algorithm, `i` goes backward (n-1->1), meaning that the "already" shuffled part of the array is never altered betweens iterations, while in the current implementation the "not-yet" shuffled part of the array is conserved between iterations. R=golang-dev CC=golang-dev https://golang.org/cl/6845121 »»» R=golang-dev, bradfitz CC=golang-dev https://golang.org/cl/6905049 --- diff --git a/src/pkg/math/rand/rand.go b/src/pkg/math/rand/rand.go index ad2bf2fac0..94f84a85fb 100644 --- a/src/pkg/math/rand/rand.go +++ b/src/pkg/math/rand/rand.go @@ -100,7 +100,7 @@ func (r *Rand) Perm(n int) []int { for i := 0; i < n; i++ { m[i] = i } - for i := 1; i < n; i++ { + for i := 0; i < n; i++ { j := r.Intn(i + 1) m[i], m[j] = m[j], m[i] }