From 637d59859d3f13a55eaab7d683b5061fcbfd616c Mon Sep 17 00:00:00 2001
From: Robert Griesemer <gri@golang.org>
Date: Thu, 11 Jun 2015 13:21:46 -0700
Subject: [PATCH] spec: clarify meaning of x op= y

Suggested by mdempsky (see also issue #11161).

Change-Id: I1ab28febe19b7a092029499015073ce8749b4d99
Reviewed-on: https://go-review.googlesource.com/10960
Reviewed-by: Ian Lance Taylor <iant@golang.org>
---
 doc/go_spec.html | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/doc/go_spec.html b/doc/go_spec.html
index b5f18f3a02..4b8d60b8e4 100644
--- a/doc/go_spec.html
+++ b/doc/go_spec.html
@@ -1,6 +1,6 @@
 <!--{
 	"Title": "The Go Programming Language Specification",
-	"Subtitle": "Version of May 26, 2015",
+	"Subtitle": "Version of June 11, 2015",
 	"Path": "/ref/spec"
 }-->
 
@@ -4388,7 +4388,7 @@ a[i] = 23
 An <i>assignment operation</i> <code>x</code> <i>op</i><code>=</code>
 <code>y</code> where <i>op</i> is a binary arithmetic operation is equivalent
 to <code>x</code> <code>=</code> <code>x</code> <i>op</i>
-<code>y</code> but evaluates <code>x</code>
+<code>(y)</code> but evaluates <code>x</code>
 only once.  The <i>op</i><code>=</code> construct is a single token.
 In assignment operations, both the left- and right-hand expression lists
 must contain exactly one single-valued expression, and the left-hand
-- 
2.48.1